1813 New Jersey gubernatorial election
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The 1813 New Jersey gubernatorial election was held on 29 October 1813 in order to elect the governor of New Jersey. Democratic-Republican nominee and former United States Attorney for the District of New Jersey William Sanford Pennington was elected by the New Jersey General Assembly against incumbent Federalist governor Aaron Ogden.[1]
General election
[edit]On election day, 29 October 1813, Democratic-Republican nominee William Sanford Pennington was elected by the New Jersey General Assembly by a margin of 10 votes against his opponent incumbent Federalist governor Aaron Ogden, thereby gaining Democratic-Republican control over the office of governor. Pennington was sworn in as the 6th governor of New Jersey that same day.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic-Republican | William Sanford Pennington | 30 | 60.00% | |
| Federalist | Aaron Ogden (incumbent) | 20 | 40.00% | |
| Total votes | 50 | 100.00% | ||
| Democratic-Republican gain from Federalist | ||||
References
[edit]- ^ "William Sanford Pennington". National Governors Association. 19 January 2010. Retrieved 20 September 2024.
- ^ "New Jersey 1813 Governor". elections.lib.tufts.edu. 11 January 2012. Retrieved 20 September 2024.
- ^ "Journal of the Legislative Council. 1813 sess". 1813. Retrieved 20 September 2024.
Categories:
- 1813 New Jersey elections
- 1813 in New Jersey
- New Jersey gubernatorial elections
- 1813 elections
- 1813 United States gubernatorial elections
- October 1813 events
- 1810s in New Jersey
- 1810s New Jersey elections
- 1813 elections in North America
- 1813 elections in the United States
- Government of New Jersey
- Indirect elections
- United States gubernatorial elections in the 1810s