Talk:Period 4 element

Change in Class

This article seems good enough to be a start class article, so i will promote iit. If anyone has any objections, please say or feel free to just change it back. --Geo7777 (talk) 15:03, 9 May 2011 (UTC)[reply]

I do, revert. I just feel this isn't Start-worthy, and none will work on it as it's not a Stub-class anymore--R8R Gtrs (talk) 19:03, 16 June 2011 (UTC)[reply]

I've changed it again because now the content is similar to that found in Period 3 element. Nevertheless it could use quite a bit more of work. Lanthanum-138 (talk) 03:52, 10 August 2011 (UTC)[reply]

The feature to note about the 4th periodic table series (IUPAC Table), is that it is the first series that is sufficiently large and complex as to allow the accumulation of an increasing quantity of "extra neutrons", defined as neutrons in excess of the A = 2Z configuration into the structure of particularly the Even Z element numbers. Thus whereas the previous excess neutron number for 16S and 18Ar was only 4, the number of extra neutrons rises to 8 for 20Ca and to 14 for 36Kr of this first 18 element series. However, since the lower limit of excess neutron number does not exceed 4, and is only 2 for 28Ni58, it can be argued that these extra neutrons are not needed for atomic stability purposes, but only the result of the availability of excess free neutrons in the milieu of the accumulation environment. It also argues for the existence of an increasing size organizational structure so that these additional extra neutrons may be distributed within the structure so as to minimize localized unbalances.WFPM (talk) 23:47, 20 September 2011 (UTC)[reply]

Concerning the presentation of this element data in the Janet Periodic table (see Charles Janet, this series of elements becomes the 5th series due to the inclusion of 3Li and 4Be as a second series, and the 4th series of the Janet table ends with the inclusion of 19K and 20Ca in the 4th series and with the addition of a 4th alpha particle to the nucleus of the atom. Then the series starts with 21Sc with 3 extra neutrons and 23V with 5 extra neutrons and thus establishes a stability trend line through this section with the formula A = 3Z - 22 and running through 26Fe 56 up to 36Kr 86 with 14 extra neutrons. And the last 2 elements in the series are 43Rb and 44Sr, where a 5th alpha particle can be included within the nucleus. Thus the accumulation process seems to be accomplished by some kind of a layer addition process, with each period ending with the addition of an additional alpha particle to the nucleus.WFPM (talk) 17:58, 22 September 2011 (UTC)[reply]

Move discussion in progress

There is a move discussion in progress on Talk:Group 3 element which affects this page. Please participate on that page and not in this talk page section. Thank you. —RMCD bot 21:15, 15 January 2013 (UTC)[reply]

Sham

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Manganese is often found free in nature…

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Iron is probably the most well-known element in period 4, being the most common element in the earth…

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For how many years is the article abandoned by qualified editors? For the record, I have no chemical education and am not even a (serious) amateur. Incnis Mrsi (talk) 16:04, 13 August 2019 (UTC)[reply]

On second thought, there is a lot of iron in the core – not as fool as I initially felt. Incnis Mrsi (talk) 16:33, 13 August 2019 (UTC)[reply]

"qualified editors"? -DePiep (talk) 16:23, 15 August 2019 (UTC)[reply]

From zinc to krypton

Zn–Kr	4s² 4p^k
	3s² 3p⁶ 3d¹⁰
	2s² 2p⁶
	1s²
Pd	5s⁰ 5p⁰
	4s² 4p⁶ 4d¹⁰ (4f⁰)
	3s² 3p⁶ 3d¹⁰
	2s² 2p⁶
	1s²
Cd–Xe	5s² 5p^k
	4s² 4p⁶ 4d¹⁰ (4f⁰)
	3s² 3p⁶ 3d¹⁰
	2s² 2p⁶
	1s²

In the 4th the depicted “n-ordered” configuration is yet possible (although is not universal). In the 5th and further there are always holes in the “shells” below the valence shell. Incnis Mrsi (talk) 14:29, 18 August 2019 (UTC)[reply]

It turned out that I stated it upside-down in the article, but fortunately another user promptly fixes my mistake. Incnis Mrsi (talk) 14:34, 18 August 2019 (UTC)[reply]

On making my OR I forgot about palladium with its 5s⁰ (although certainly knew about that). May we deem that the empty n = 5 is its valence shell anyway? Then there are indeed holes below it, but there are no holes at n < 4. Incnis Mrsi (talk) 21:04, 18 August 2019 (UTC)[reply]

@Incnis Mrsi: The d-elements up to group 10 are usually dⁿs⁰ in chemical environments (10.1002/anie.200800827), so the main valence shell is usually the (n−1)d-shell (although there can be some small ns contributions). The electron configurations of free atoms are not always the same as those in compounds! Double sharp (talk) 08:13, 19 August 2019 (UTC)[reply]